Factor 125+216w^3

Math
125+216w3
Rewrite 125 as 53.
53+216w3
Rewrite 216w3 as (6w)3.
53+(6w)3
Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2-ab+b2) where a=5 and b=6w.
(5+6w)(52-5(6w)+(6w)2)
Simplify.
Tap for more steps…
Raise 5 to the power of 2.
(5+6w)(25-5(6w)+(6w)2)
Multiply 6 by -5.
(5+6w)(25-30w+(6w)2)
Apply the product rule to 6w.
(5+6w)(25-30w+62w2)
Raise 6 to the power of 2.
(5+6w)(25-30w+36w2)
(5+6w)(25-30w+36w2)
Factor 125+216w^3

Solving MATH problems

We can solve all math problems. Get help on the web or with our math app

Scroll to top