Factor 64c^4+27c

Math
64c4+27c
Factor c out of 64c4+27c.
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Factor c out of 64c4.
c(64c3)+27c
Factor c out of 27c.
c(64c3)+c⋅27
Factor c out of c(64c3)+c⋅27.
c(64c3+27)
c(64c3+27)
Rewrite 64c3 as (4c)3.
c((4c)3+27)
Rewrite 27 as 33.
c((4c)3+33)
Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2-ab+b2) where a=4c and b=3.
c((4c+3)((4c)2-(4c)⋅3+32))
Factor.
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Simplify.
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Apply the product rule to 4c.
c((4c+3)(42c2-(4c)⋅3+32))
Raise 4 to the power of 2.
c((4c+3)(16c2-(4c)⋅3+32))
Multiply 4 by -1.
c((4c+3)(16c2-4c⋅3+32))
Multiply 3 by -4.
c((4c+3)(16c2-12c+32))
Raise 3 to the power of 2.
c((4c+3)(16c2-12c+9))
c((4c+3)(16c2-12c+9))
Remove unnecessary parentheses.
c(4c+3)(16c2-12c+9)
c(4c+3)(16c2-12c+9)
Factor 64c^4+27c

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