k3+512
Rewrite 512 as 83.
k3+83
Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2-ab+b2) where a=k and b=8.
(k+8)(k2-k⋅8+82)
Multiply 8 by -1.
(k+8)(k2-8k+82)
Raise 8 to the power of 2.
(k+8)(k2-8k+64)
(k+8)(k2-8k+64)
Factor k^3+512