Factor ((y^2-18x+81)/(y^2-3x-54))÷((y^2-81)/6)

Math
y2-18x+81y2-3x-54÷y2-816
Rewrite 81 as 92.
y2-18x+81y2-3x-54y2-926
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b) where a=y and b=9.
y2-18x+81y2-3x-54(y+9)(y-9)6
Factor ((y^2-18x+81)/(y^2-3x-54))÷((y^2-81)/6)

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