# Find the Surface Area cylinder (6)(2)

h=6r=2
The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.
2π⋅(radius)2+2π⋅(radius)⋅(height)
Substitute the values of the radius r=2 and height h=6 into the formula. Pi π is approximately equal to 3.14.
2(π)(2)2+2(π)(2)(6)
Simplify each term.
Multiply 2 by (2)2 by adding the exponents.
Move (2)2.
(2)2⋅2π+2(π)(2)(6)
Multiply (2)2 by 2.
Raise 2 to the power of 1.
(2)2⋅21π+2(π)(2)(6)
Use the power rule aman=am+n to combine exponents.
22+1π+2(π)(2)(6)
22+1π+2(π)(2)(6)
Add 2 and 1.
23π+2(π)(2)(6)
23π+2(π)(2)(6)
Raise 2 to the power of 3.
8π+2(π)(2)(6)
Multiply 2 by 2.
8π+4π⋅6
Multiply 6 by 4.
8π+24π
8π+24π
Add 8π and 24π.
32π
The result can be shown in multiple forms.
Exact Form:
32π
Decimal Form:
100.53096491…
Find the Surface Area cylinder (6)(2)

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