Find the Surface Area cylinder (7sm)(9sm)

Math
h=7smr=9sm
The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.
2π⋅(radius)2+2π⋅(radius)⋅(height)
Substitute the values of the radius r=9 and height h=7 into the formula. Pi π is approximately equal to 3.14.
2(π)(9)2+2(π)(9)(7)
Simplify each term.
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Raise 9 to the power of 2.
2π⋅81+2(π)(9)(7)
Multiply 81 by 2.
162π+2(π)(9)(7)
Multiply 9 by 2.
162π+18π⋅7
Multiply 7 by 18.
162π+126π
162π+126π
Add 162π and 126π.
288π(sm)2
Find the Surface Area cylinder (7sm)(9sm)

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