# Find the Surface Area cylinder (8)(3)

h=8r=3
The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.
2π⋅(radius)2+2π⋅(radius)⋅(height)
Substitute the values of the radius r=3 and height h=8 into the formula. Pi π is approximately equal to 3.14.
2(π)(3)2+2(π)(3)(8)
Simplify each term.
Raise 3 to the power of 2.
2π⋅9+2(π)(3)(8)
Multiply 9 by 2.
18π+2(π)(3)(8)
Multiply 3 by 2.
18π+6π⋅8
Multiply 8 by 6.
18π+48π
18π+48π
Add 18π and 48π.
66π
The result can be shown in multiple forms.
Exact Form:
66π
Decimal Form:
207.34511513…
Find the Surface Area cylinder (8)(3)

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