# Find the Variance 9.58 , 9.69

9.58 , 9.69
The mean of a set of numbers is the sum divided by the number of terms.
x&OverBar;=9.58+9.692
x&OverBar;=19.272
Divide 19.27 by 2.
x&OverBar;=9.635
The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.
x&OverBar;=9.635
Set up the formula for variance. The variance of a set of values is a measure of the spread of its values.
s2=∑i=1n⁡(xi-xavg)2n-1
Set up the formula for variance for this set of numbers.
s=(9.58-9.635)2+(9.69-9.635)22-1
Simplify the result.
Simplify the numerator.
Subtract 9.635 from 9.58.
s=(-0.055)2+(9.69-9.635)22-1
Raise -0.055 to the power of 2.
s=0.003025+(9.69-9.635)22-1
Subtract 9.635 from 9.69.
s=0.003025+0.05522-1
Raise 0.055 to the power of 2.
s=0.003025+0.0030252-1
s=0.006052-1
s=0.006052-1
Simplify the expression.
Subtract 1 from 2.
s=0.006051
Divide 0.00605 by 1.
s=0.00605
s=0.00605
s=0.00605
Approximate the result.
s2≈0.006
Find the Variance 9.58 , 9.69

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