Solve for a 0=a^2-13a+57

Math
0=a2-13a+57
Rewrite the equation as a2-13a+57=0.
a2-13a+57=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=-13, and c=57 into the quadratic formula and solve for a.
13±(-13)2-4⋅(1⋅57)2⋅1
Simplify.
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Simplify the numerator.
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Raise -13 to the power of 2.
a=13±169-4⋅(1⋅57)2⋅1
Multiply 57 by 1.
a=13±169-4⋅572⋅1
Multiply -4 by 57.
a=13±169-2282⋅1
Subtract 228 from 169.
a=13±-592⋅1
Rewrite -59 as -1(59).
a=13±-1⋅592⋅1
Rewrite -1(59) as -1⋅59.
a=13±-1⋅592⋅1
Rewrite -1 as i.
a=13±i592⋅1
a=13±i592⋅1
Multiply 2 by 1.
a=13±i592
a=13±i592
The final answer is the combination of both solutions.
a=13+i592,13-i592
Solve for a 0=a^2-13a+57

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