Solve for a 2a-3b+c=10

Math
2a-3b+c=10
Move all terms not containing a to the right side of the equation.
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Add 3b to both sides of the equation.
2a+c=10+3b
Subtract c from both sides of the equation.
2a=10+3b-c
2a=10+3b-c
Divide each term by 2 and simplify.
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Divide each term in 2a=10+3b-c by 2.
2a2=102+3b2+-c2
Cancel the common factor of 2.
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Cancel the common factor.
2a2=102+3b2+-c2
Divide a by 1.
a=102+3b2+-c2
a=102+3b2+-c2
Simplify each term.
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Divide 10 by 2.
a=5+3b2+-c2
Move the negative in front of the fraction.
a=5+3b2-c2
a=5+3b2-c2
a=5+3b2-c2
Solve for a 2a-3b+c=10

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