Solve for a 4(2a-1)=-10(a-5)

Math
4(2a-1)=-10(a-5)
Simplify 4(2a-1).
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Apply the distributive property.
4(2a)+4⋅-1=-10(a-5)
Multiply.
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Multiply 2 by 4.
8a+4⋅-1=-10(a-5)
Multiply 4 by -1.
8a-4=-10(a-5)
8a-4=-10(a-5)
8a-4=-10(a-5)
Simplify -10(a-5).
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Apply the distributive property.
8a-4=-10a-10⋅-5
Multiply -10 by -5.
8a-4=-10a+50
8a-4=-10a+50
Move all terms containing a to the left side of the equation.
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Add 10a to both sides of the equation.
8a-4+10a=50
Add 8a and 10a.
18a-4=50
18a-4=50
Move all terms not containing a to the right side of the equation.
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Add 4 to both sides of the equation.
18a=50+4
Add 50 and 4.
18a=54
18a=54
Divide each term by 18 and simplify.
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Divide each term in 18a=54 by 18.
18a18=5418
Cancel the common factor of 18.
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Cancel the common factor.
18a18=5418
Divide a by 1.
a=5418
a=5418
Divide 54 by 18.
a=3
a=3
Solve for a 4(2a-1)=-10(a-5)

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