Solve for a 4a^2+9a+1=0

Math
4a2+9a+1=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=4, b=9, and c=1 into the quadratic formula and solve for a.
-9±92-4⋅(4⋅1)2⋅4
Simplify.
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Simplify the numerator.
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Raise 9 to the power of 2.
a=-9±81-4⋅(4⋅1)2⋅4
Multiply 4 by 1.
a=-9±81-4⋅42⋅4
Multiply -4 by 4.
a=-9±81-162⋅4
Subtract 16 from 81.
a=-9±652⋅4
a=-9±652⋅4
Multiply 2 by 4.
a=-9±658
a=-9±658
The final answer is the combination of both solutions.
a=-9-658,-9+658
The result can be shown in multiple forms.
Exact Form:
a=-9-658,-9+658
Decimal Form:
a=-0.11721778…,-2.13278221…
Solve for a 4a^2+9a+1=0

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