# Solve for a 5/(7a)*(3a)/20=(3a)/(28a) 57a⋅3a20=3a28a
Factor each term.
Multiply 57a by 3a20.
57a⋅3a20=3a28a
Multiply 57a and 3a20.
5(3a)7a⋅20=3a28a
Reduce the expression 3a28a by cancelling the common factors.
Cancel the common factor.
5(3a)7a⋅20=3a28a
Rewrite the expression.
5(3a)7a⋅20=328
5(3a)7a⋅20=328
Reduce the expression 5(3a)7a⋅20 by cancelling the common factors.
Factor 5 out of 7a⋅20.
5(3a)5(7a⋅4)=328
Cancel the common factor.
5(3a)5(7a⋅4)=328
Rewrite the expression.
3a7a⋅4=328
3a7a⋅4=328
Reduce the expression 3a7a⋅4 by cancelling the common factors.
Cancel the common factor.
3a7a⋅4=328
Rewrite the expression.
37⋅4=328
37⋅4=328
Multiply 7 by 4.
328=328
328=328
Since the expression on each side of the equation has the same denominator, the numerators must be equal.
3=3
Since 3=3, the equation will always be true for any value of a.
All real numbers
The result can be shown in multiple forms.
All real numbers
Interval Notation:
(-∞,∞)
Solve for a 5/(7a)*(3a)/20=(3a)/(28a)

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