# Solve for a a^2=-35-12a a2=-35-12a
Add 12a to both sides of the equation.
a2+12a=-35
Move 35 to the left side of the equation by adding it to both sides.
a2+12a+35=0
Factor a2+12a+35 using the AC method.
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 35 and whose sum is 12.
5,7
Write the factored form using these integers.
(a+5)(a+7)=0
(a+5)(a+7)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
a+5=0
a+7=0
Set the first factor equal to 0 and solve.
Set the first factor equal to 0.
a+5=0
Subtract 5 from both sides of the equation.
a=-5
a=-5
Set the next factor equal to 0 and solve.
Set the next factor equal to 0.
a+7=0
Subtract 7 from both sides of the equation.
a=-7
a=-7
The final solution is all the values that make (a+5)(a+7)=0 true.
a=-5,-7
Solve for a a^2=-35-12a

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