# Solve for a a^2+5a-4a=6

a2+5a-4a=6
Subtract 4a from 5a.
a2+a=6
Move 6 to the left side of the equation by subtracting it from both sides.
a2+a-6=0
Factor a2+a-6 using the AC method.
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -6 and whose sum is 1.
-2,3
Write the factored form using these integers.
(a-2)(a+3)=0
(a-2)(a+3)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
a-2=0
a+3=0
Set the first factor equal to 0 and solve.
Set the first factor equal to 0.
a-2=0
Add 2 to both sides of the equation.
a=2
a=2
Set the next factor equal to 0 and solve.
Set the next factor equal to 0.
a+3=0
Subtract 3 from both sides of the equation.
a=-3
a=-3
The final solution is all the values that make (a-2)(a+3)=0 true.
a=2,-3
Solve for a a^2+5a-4a=6

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