Solve for A A^2+A=72

Math
A2+A=72
Move 72 to the left side of the equation by subtracting it from both sides.
A2+A-72=0
Factor A2+A-72 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -72 and whose sum is 1.
-8,9
Write the factored form using these integers.
(A-8)(A+9)=0
(A-8)(A+9)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
A-8=0
A+9=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
A-8=0
Add 8 to both sides of the equation.
A=8
A=8
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
A+9=0
Subtract 9 from both sides of the equation.
A=-9
A=-9
The final solution is all the values that make (A-8)(A+9)=0 true.
A=8,-9
Solve for A A^2+A=72

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