# Solve for a sin(a)=0.172

sin(a)=0.172
Take the inverse sine of both sides of the equation to extract a from inside the sine.
a=arcsin(0.172)
Evaluate arcsin(0.172).
a=0.17285956
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
a=(3.14159265)-0.17285956
Simplify the expression to find the second solution.
Remove the parentheses around the expression 3.14159265.
a=3.14159265-0.17285956
Subtract 0.17285956 from 3.14159265.
a=2.96873308
a=2.96873308
Find the period.
The period of the function can be calculated using 2π|b|.
2π|b|
Replace b with 1 in the formula for period.
2π|1|
Solve the equation.
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Divide 2π by 1.
The period of the sin(a) function is 2π so values will repeat every 2π radians in both directions.
a=0.17285956+2πn,2.96873308+2πn, for any integer n
Solve for a sin(a)=0.172

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