Solve for b 240=1/2*(34+b)*12

Math
240=12⋅(34+b)⋅12
Rewrite the equation as 12⋅(34+b)⋅12=240.
12⋅(34+b)⋅12=240
Simplify.
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Apply the distributive property.
(12⋅34+12b)⋅12=240
Cancel the common factor of 2.
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Factor 2 out of 34.
(12⋅(2(17))+12b)⋅12=240
Cancel the common factor.
(12⋅(2⋅17)+12b)⋅12=240
Rewrite the expression.
(17+12b)⋅12=240
(17+12b)⋅12=240
Combine 12 and b.
(17+b2)⋅12=240
(17+b2)⋅12=240
Divide each term by 6 and simplify.
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Divide each term in (17+b2)⋅12=240 by 6.
(17+b2)⋅126=2406
Simplify (17+b2)⋅126.
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Cancel the common factor of 12 and 6.
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Factor 6 out of (17+b2)⋅12.
6((17+b2)⋅2)6=2406
Cancel the common factors.
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Factor 6 out of 6.
6((17+b2)⋅2)6(1)=2406
Cancel the common factor.
6((17+b2)⋅2)6⋅1=2406
Rewrite the expression.
(17+b2)⋅21=2406
Divide (17+b2)⋅2 by 1.
(17+b2)⋅2=2406
(17+b2)⋅2=2406
(17+b2)⋅2=2406
Apply the distributive property.
17⋅2+b2⋅2=2406
Multiply 17 by 2.
34+b2⋅2=2406
Cancel the common factor of 2.
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Cancel the common factor.
34+b2⋅2=2406
Rewrite the expression.
34+b=2406
34+b=2406
34+b=2406
Divide 240 by 6.
34+b=40
34+b=40
Move all terms not containing b to the right side of the equation.
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Subtract 34 from both sides of the equation.
b=40-34
Subtract 34 from 40.
b=6
b=6
Solve for b 240=1/2*(34+b)*12

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