Solve for b 40+7b=-7b-6(4-5b)

$40 + 7 b = - 7 b - 6 (4 - 5 b)$

Since $b$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 7 b - 6 (4 - 5 b) = 40 + 7 b$

Simplify $- 7 b - 6 (4 - 5 b)$ .

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Simplify each term.

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Apply the distributive property.

$- 7 b - 6 \cdot 4 - 6 (- 5 b) = 40 + 7 b$

Multiply $- 6$ by $4$ .

$- 7 b - 24 - 6 (- 5 b) = 40 + 7 b$

Multiply $- 5$ by $- 6$ .

$- 7 b - 24 + 30 b = 40 + 7 b$

Add $- 7 b$ and $30 b$ .

$23 b - 24 = 40 + 7 b$

Move all terms containing $b$ to the left side of the equation.

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Subtract $7 b$ from both sides of the equation.

$23 b - 24 - 7 b = 40$

Subtract $7 b$ from $23 b$ .

$16 b - 24 = 40$

Move all terms not containing $b$ to the right side of the equation.

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Add $24$ to both sides of the equation.

$16 b = 40 + 24$

Add $40$ and $24$ .

$16 b = 64$

Divide each term by $16$ and simplify.

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Divide each term in $16 b = 64$ by $16$ .

$\frac{16 b}{16} = \frac{64}{16}$

Cancel the common factor of $16$ .

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Cancel the common factor.

$\frac{16 b}{16} = \frac{64}{16}$

Divide $b$ by $1$ .

$b = \frac{64}{16}$

Divide $64$ by $16$ .

$b = 4$

Solve for b 40+7b=-7b-6(4-5b)