Solve for b 4+b^2=5b

Math
4+b2=5b
Subtract 5b from both sides of the equation.
4+b2-5b=0
Factor 4+b2-5b using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 4 and whose sum is -5.
-4,-1
Write the factored form using these integers.
(b-4)(b-1)=0
(b-4)(b-1)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
b-4=0
b-1=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
b-4=0
Add 4 to both sides of the equation.
b=4
b=4
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
b-1=0
Add 1 to both sides of the equation.
b=1
b=1
The final solution is all the values that make (b-4)(b-1)=0 true.
b=4,1
Solve for b 4+b^2=5b

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