Solve for b 5(3b-10)=10

Math
5(3b-10)=10
Divide each term by 5 and simplify.
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Divide each term in 5(3b-10)=10 by 5.
5(3b-10)5=105
Cancel the common factor of 5.
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Cancel the common factor.
5(3b-10)5=105
Divide 3b-10 by 1.
3b-10=105
3b-10=105
Divide 10 by 5.
3b-10=2
3b-10=2
Move all terms not containing b to the right side of the equation.
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Add 10 to both sides of the equation.
3b=2+10
Add 2 and 10.
3b=12
3b=12
Divide each term by 3 and simplify.
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Divide each term in 3b=12 by 3.
3b3=123
Cancel the common factor of 3.
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Cancel the common factor.
3b3=123
Divide b by 1.
b=123
b=123
Divide 12 by 3.
b=4
b=4
Solve for b 5(3b-10)=10

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