Solve for b -5(b+2)+8b=2

Math
-5(b+2)+8b=2
Simplify -5(b+2)+8b.
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Simplify each term.
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Apply the distributive property.
-5b-5⋅2+8b=2
Multiply -5 by 2.
-5b-10+8b=2
-5b-10+8b=2
Add -5b and 8b.
3b-10=2
3b-10=2
Move all terms not containing b to the right side of the equation.
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Add 10 to both sides of the equation.
3b=2+10
Add 2 and 10.
3b=12
3b=12
Divide each term by 3 and simplify.
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Divide each term in 3b=12 by 3.
3b3=123
Cancel the common factor of 3.
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Cancel the common factor.
3b3=123
Divide b by 1.
b=123
b=123
Divide 12 by 3.
b=4
b=4
Solve for b -5(b+2)+8b=2

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