Solve for c 4c+1+3c+2+2c+3+c+4=5(2x+2)

Math
4c+1+3c+2+2c+3+c+4=5(2x+2)
Simplify 4c+1+3c+2+2c+3+c+4.
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Add 4c and 3c.
7c+1+2+2c+3+c+4=5(2x+2)
Add 7c and 2c.
9c+1+2+3+c+4=5(2x+2)
Add 9c and c.
10c+1+2+3+4=5(2x+2)
Simplify by adding numbers.
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Add 1 and 2.
10c+3+3+4=5(2x+2)
Add 3 and 3.
10c+6+4=5(2x+2)
Add 6 and 4.
10c+10=5(2x+2)
10c+10=5(2x+2)
10c+10=5(2x+2)
Simplify 5(2x+2).
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Apply the distributive property.
10c+10=5(2x)+5⋅2
Multiply.
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Multiply 2 by 5.
10c+10=10x+5⋅2
Multiply 5 by 2.
10c+10=10x+10
10c+10=10x+10
10c+10=10x+10
Move all terms not containing c to the right side of the equation.
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Subtract 10 from both sides of the equation.
10c=10x+10-10
Combine the opposite terms in 10x+10-10.
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Subtract 10 from 10.
10c=10x+0
Add 10x and 0.
10c=10x
10c=10x
10c=10x
Divide each term by 10 and simplify.
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Divide each term in 10c=10x by 10.
10c10=10×10
Cancel the common factor of 10.
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Cancel the common factor.
10c10=10×10
Divide c by 1.
c=10×10
c=10×10
Cancel the common factor of 10.
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Cancel the common factor.
c=10×10
Divide x by 1.
c=x
c=x
c=x
Solve for c 4c+1+3c+2+2c+3+c+4=5(2x+2)

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