Solve for c 5(4c-1)-1=16c+2

Math
5(4c-1)-1=16c+2
Simplify 5(4c-1)-1.
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Simplify each term.
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Apply the distributive property.
5(4c)+5⋅-1-1=16c+2
Multiply 4 by 5.
20c+5⋅-1-1=16c+2
Multiply 5 by -1.
20c-5-1=16c+2
20c-5-1=16c+2
Subtract 1 from -5.
20c-6=16c+2
20c-6=16c+2
Move all terms containing c to the left side of the equation.
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Subtract 16c from both sides of the equation.
20c-6-16c=2
Subtract 16c from 20c.
4c-6=2
4c-6=2
Move all terms not containing c to the right side of the equation.
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Add 6 to both sides of the equation.
4c=2+6
Add 2 and 6.
4c=8
4c=8
Divide each term by 4 and simplify.
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Divide each term in 4c=8 by 4.
4c4=84
Cancel the common factor of 4.
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Cancel the common factor.
4c4=84
Divide c by 1.
c=84
c=84
Divide 8 by 4.
c=2
c=2
Solve for c 5(4c-1)-1=16c+2

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