Solve for c a+3b+5c=94

$a + 3 b + 5 c = 94$

Move all terms not containing $c$ to the right side of the equation.

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Subtract $a$ from both sides of the equation.

$3 b + 5 c = 94 - a$

Subtract $3 b$ from both sides of the equation.

$5 c = 94 - a - 3 b$

Divide each term by $5$ and simplify.

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Divide each term in $5 c = 94 - a - 3 b$ by $5$ .

$\frac{5 c}{5} = \frac{94}{5} + \frac{- a}{5} + \frac{- 3 b}{5}$

Cancel the common factor of $5$ .

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Cancel the common factor.

$\frac{5 c}{5} = \frac{94}{5} + \frac{- a}{5} + \frac{- 3 b}{5}$

Divide $c$ by $1$ .

$c = \frac{94}{5} + \frac{- a}{5} + \frac{- 3 b}{5}$

Simplify each term.

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Move the negative in front of the fraction.

$c = \frac{94}{5} - \frac{a}{5} + \frac{- 3 b}{5}$

Move the negative in front of the fraction.

$c = \frac{94}{5} - \frac{a}{5} - \frac{3 b}{5}$

Solve for c a+3b+5c=94