Solve for j 3(6-4j-27j)=10j-31

3(6-4j-27j)=10j-31

Simplify 3(6-4j-27j).

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Subtract 27j from -4j.

3(6-31j)=10j-31

Apply the distributive property.

3⋅6+3(-31j)=10j-31

Multiply.

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Multiply 3 by 6.

18+3(-31j)=10j-31

Multiply -31 by 3.

18-93j=10j-31

Move all terms containing j to the left side of the equation.

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Subtract 10j from both sides of the equation.

18-93j-10j=-31

Subtract 10j from -93j.

18-103j=-31

Move all terms not containing j to the right side of the equation.

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Subtract 18 from both sides of the equation.

-103j=-31-18

Subtract 18 from -31.

-103j=-49

Divide each term by -103 and simplify.

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Divide each term in -103j=-49 by -103.

-103j-103=-49-103

Cancel the common factor of -103.

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Cancel the common factor.

-103j-103=-49-103

Divide j by 1.

j=-49-103

Dividing two negative values results in a positive value.

j=49103

The result can be shown in multiple forms.

Exact Form:

j=49103

Decimal Form:

j=0.47572815…

Solve for j 3(6-4j-27j)=10j-31