Solve for k -4(k-2)+14=3k-20

$- 4 (k - 2) + 14 = 3 k - 20$

Simplify $- 4 (k - 2) + 14$ .

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Simplify each term.

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Apply the distributive property.

$- 4 k - 4 \cdot - 2 + 14 = 3 k - 20$

Multiply $- 4$ by $- 2$ .

$- 4 k + 8 + 14 = 3 k - 20$

Add $8$ and $14$ .

$- 4 k + 22 = 3 k - 20$

Move all terms containing $k$ to the left side of the equation.

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Subtract $3 k$ from both sides of the equation.

$- 4 k + 22 - 3 k = - 20$

Subtract $3 k$ from $- 4 k$ .

$- 7 k + 22 = - 20$

Move all terms not containing $k$ to the right side of the equation.

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Subtract $22$ from both sides of the equation.

$- 7 k = - 20 - 22$

Subtract $22$ from $- 20$ .

$- 7 k = - 42$

Divide each term by $- 7$ and simplify.

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Divide each term in $- 7 k = - 42$ by $- 7$ .

$\frac{- 7 k}{- 7} = \frac{- 42}{- 7}$

Cancel the common factor of $- 7$ .

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Cancel the common factor.

$\frac{- 7 k}{- 7} = \frac{- 42}{- 7}$

Divide $k$ by $1$ .

$k = \frac{- 42}{- 7}$

Divide $- 42$ by $- 7$ .

$k = 6$

Solve for k -4(k-2)+14=3k-20