Solve for K 6=(K(18))/(3^2)

Math
6=K(18)32
Rewrite the equation as K(18)32=6.
K(18)32=6
Multiply both sides of the equation by 3218.
3218⋅K(18)32=3218⋅6
Simplify both sides of the equation.
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Simplify 3218⋅K(18)32.
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Evaluate the exponents.
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Raise 3 to the power of 2.
918⋅K(18)32=3218⋅6
Raise 3 to the power of 2.
918⋅K⋅189=3218⋅6
918⋅K⋅189=3218⋅6
Cancel the common factor of 9.
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Cancel the common factor.
918⋅K⋅189=3218⋅6
Rewrite the expression.
118⋅(K⋅18)=3218⋅6
118⋅(K⋅18)=3218⋅6
Cancel the common factor of 18.
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Factor 18 out of K⋅18.
118⋅(18⋅K)=3218⋅6
Cancel the common factor.
118⋅(18⋅K)=3218⋅6
Rewrite the expression.
K=3218⋅6
K=3218⋅6
K=3218⋅6
Simplify 3218⋅6.
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Raise 3 to the power of 2.
K=918⋅6
Cancel the common factor of 6.
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Factor 6 out of 18.
K=96(3)⋅6
Cancel the common factor.
K=96⋅3⋅6
Rewrite the expression.
K=93
K=93
Divide 9 by 3.
K=3
K=3
K=3
Solve for K 6=(K(18))/(3^2)

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