Solve for m -3^2+m(-3)+n=0

$- 3^{2} + m (- 3) + n = 0$

Simplify each term.

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Raise $3$ to the power of $2$ .

$- 1 \cdot 9 + m (- 3) + n = 0$

Multiply $- 1$ by $9$ .

$- 9 + m (- 3) + n = 0$

Move $- 3$ to the left of $m$ .

$- 9 - 3 m + n = 0$

Move all terms not containing $m$ to the right side of the equation.

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Add $9$ to both sides of the equation.

$- 3 m + n = 9$

Subtract $n$ from both sides of the equation.

$- 3 m = 9 - n$

Divide each term by $- 3$ and simplify.

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Divide each term in $- 3 m = 9 - n$ by $- 3$ .

$\frac{- 3 m}{- 3} = \frac{9}{- 3} + \frac{- n}{- 3}$

Cancel the common factor of $- 3$ .

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Cancel the common factor.

$\frac{- 3 m}{- 3} = \frac{9}{- 3} + \frac{- n}{- 3}$

Divide $m$ by $1$ .

$m = \frac{9}{- 3} + \frac{- n}{- 3}$

Simplify each term.

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Divide $9$ by $- 3$ .

$m = - 3 + \frac{- n}{- 3}$

Dividing two negative values results in a positive value.

$m = - 3 + \frac{n}{3}$

Solve for m -3^2+m(-3)+n=0