Solve for n 2^(2n+1)=32

Math
22n+1=32
Create equivalent expressions in the equation that all have equal bases.
22n+1=25
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
2n+1=5
Solve for n.
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Move all terms not containing n to the right side of the equation.
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Subtract 1 from both sides of the equation.
2n=5-1
Subtract 1 from 5.
2n=4
2n=4
Divide each term by 2 and simplify.
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Divide each term in 2n=4 by 2.
2n2=42
Cancel the common factor of 2.
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Cancel the common factor.
2n2=42
Divide n by 1.
n=42
n=42
Divide 4 by 2.
n=2
n=2
n=2
Solve for n 2^(2n+1)=32

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