Solve for n n^2-10n+21=0

Math
n2-10n+21=0
Factor n2-10n+21 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 21 and whose sum is -10.
-7,-3
Write the factored form using these integers.
(n-7)(n-3)=0
(n-7)(n-3)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
n-7=0
n-3=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
n-7=0
Add 7 to both sides of the equation.
n=7
n=7
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
n-3=0
Add 3 to both sides of the equation.
n=3
n=3
The final solution is all the values that make (n-7)(n-3)=0 true.
n=7,3
Solve for n n^2-10n+21=0

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