n2+3n-18=0

Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -18 and whose sum is 3.

-3,6

Write the factored form using these integers.

(n-3)(n+6)=0

(n-3)(n+6)=0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

n-3=0

n+6=0

Set the first factor equal to 0.

n-3=0

Add 3 to both sides of the equation.

n=3

n=3

Set the next factor equal to 0.

n+6=0

Subtract 6 from both sides of the equation.

n=-6

n=-6

The final solution is all the values that make (n-3)(n+6)=0 true.

n=3,-6

Solve for n n^2+3n-18=0