Solve for r 3r^2=5-r

Math
3r2=5-r
Add r to both sides of the equation.
3r2+r=5
Move 5 to the left side of the equation by subtracting it from both sides.
3r2+r-5=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=3, b=1, and c=-5 into the quadratic formula and solve for r.
-1±12-4⋅(3⋅-5)2⋅3
Simplify.
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Simplify the numerator.
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One to any power is one.
r=-1±1-4⋅(3⋅-5)2⋅3
Multiply 3 by -5.
r=-1±1-4⋅-152⋅3
Multiply -4 by -15.
r=-1±1+602⋅3
Add 1 and 60.
r=-1±612⋅3
r=-1±612⋅3
Multiply 2 by 3.
r=-1±616
r=-1±616
The final answer is the combination of both solutions.
r=-1-616,-1+616
The result can be shown in multiple forms.
Exact Form:
r=-1-616,-1+616
Decimal Form:
r=1.13504161…,-1.46837494…
Solve for r 3r^2=5-r

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