Solve for ? sin(x)=(90.4*9.8)÷4820

Math
sin(x)=90.4⋅9.8÷4820
Take the inverse sine of both sides of the equation to extract x from inside the sine.
x=arcsin(0.18380082)
Evaluate arcsin(0.18380082).
x=0.18485176
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
x=(3.14159265)-0.18485176
Simplify the expression to find the second solution.
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Remove the parentheses around the expression 3.14159265.
x=3.14159265-0.18485176
Subtract 0.18485176 from 3.14159265.
x=2.95674088
x=2.95674088
Find the period of sin(x).
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The period of the function can be calculated using 2π|b|.
2π|b|
Replace b with 1 in the formula for period.
2π|1|
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Divide 2π by 1.
The period of the sin(x) function is 2π so values will repeat every 2π radians in both directions.
x=0.18485176+2πn,2.95674088+2πn, for any integer n
Solve for ? sin(x)=(90.4*9.8)÷4820

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