Solve for w w^2-2w-8=0

Math
w2-2w-8=0
Factor w2-2w-8 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -8 and whose sum is -2.
-4,2
Write the factored form using these integers.
(w-4)(w+2)=0
(w-4)(w+2)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
w-4=0
w+2=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
w-4=0
Add 4 to both sides of the equation.
w=4
w=4
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
w+2=0
Subtract 2 from both sides of the equation.
w=-2
w=-2
The final solution is all the values that make (w-4)(w+2)=0 true.
w=4,-2
Solve for w w^2-2w-8=0

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