Solve for y 18-4y=8-2(1+8y)

$18 - 4 y = 8 - 2 (1 + 8 y)$

Simplify $8 - 2 (1 + 8 y)$ .

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Simplify each term.

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Apply the distributive property.

$18 - 4 y = 8 - 2 \cdot 1 - 2 (8 y)$

Multiply $- 2$ by $1$ .

$18 - 4 y = 8 - 2 - 2 (8 y)$

Multiply $8$ by $- 2$ .

$18 - 4 y = 8 - 2 - 16 y$

Subtract $2$ from $8$ .

$18 - 4 y = 6 - 16 y$

Move all terms containing $y$ to the left side of the equation.

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Add $16 y$ to both sides of the equation.

$18 - 4 y + 16 y = 6$

Add $- 4 y$ and $16 y$ .

$18 + 12 y = 6$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $18$ from both sides of the equation.

$12 y = 6 - 18$

Subtract $18$ from $6$ .

$12 y = - 12$

Divide each term by $12$ and simplify.

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Divide each term in $12 y = - 12$ by $12$ .

$\frac{12 y}{12} = \frac{- 12}{12}$

Cancel the common factor of $12$ .

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Cancel the common factor.

$\frac{12 y}{12} = \frac{- 12}{12}$

Divide $y$ by $1$ .

$y = \frac{- 12}{12}$

Divide $- 12$ by $12$ .

$y = - 1$

Solve for y 18-4y=8-2(1+8y)