Solve for y 2(5y+3)=10y+6

Math
2(5y+3)=10y+6
Simplify 2(5y+3).
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Apply the distributive property.
2(5y)+2⋅3=10y+6
Multiply.
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Multiply 5 by 2.
10y+2⋅3=10y+6
Multiply 2 by 3.
10y+6=10y+6
10y+6=10y+6
10y+6=10y+6
Move all terms containing y to the left side of the equation.
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Subtract 10y from both sides of the equation.
10y+6-10y=6
Combine the opposite terms in 10y+6-10y.
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Subtract 10y from 10y.
0+6=6
Add 0 and 6.
6=6
6=6
6=6
Since 6=6, the equation will always be true for any value of y.
All real numbers
The result can be shown in multiple forms.
All real numbers
Interval Notation:
(-∞,∞)
Solve for y 2(5y+3)=10y+6

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