Solve for y 3y^2+4y-2=0

Math
3y2+4y-2=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=3, b=4, and c=-2 into the quadratic formula and solve for y.
-4±42-4⋅(3⋅-2)2⋅3
Simplify.
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Simplify the numerator.
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Raise 4 to the power of 2.
y=-4±16-4⋅(3⋅-2)2⋅3
Multiply 3 by -2.
y=-4±16-4⋅-62⋅3
Multiply -4 by -6.
y=-4±16+242⋅3
Add 16 and 24.
y=-4±402⋅3
Rewrite 40 as 22⋅10.
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Factor 4 out of 40.
y=-4±4(10)2⋅3
Rewrite 4 as 22.
y=-4±22⋅102⋅3
y=-4±22⋅102⋅3
Pull terms out from under the radical.
y=-4±2102⋅3
y=-4±2102⋅3
Multiply 2 by 3.
y=-4±2106
Simplify -4±2106.
y=-2±103
y=-2±103
The final answer is the combination of both solutions.
y=-2-103,-2+103
The result can be shown in multiple forms.
Exact Form:
y=-2-103,-2+103
Decimal Form:
y=0.38742588…,-1.72075922…
Solve for y 3y^2+4y-2=0

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