Solve for y 5y^2+2y=4y^2-1

Math
5y2+2y=4y2-1
Move all terms containing y to the left side of the equation.
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Subtract 4y2 from both sides of the equation.
5y2+2y-4y2=-1
Subtract 4y2 from 5y2.
y2+2y=-1
y2+2y=-1
Move 1 to the left side of the equation by adding it to both sides.
y2+2y+1=0
Factor using the perfect square rule.
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Rewrite 1 as 12.
y2+2y+12=0
Check the middle term by multiplying 2ab and compare this result with the middle term in the original expression.
2ab=2⋅y⋅1
Simplify.
2ab=2y
Factor using the perfect square trinomial rule a2+2ab+b2=(a+b)2, where a=y and b=1.
(y+1)2=0
(y+1)2=0
Set the y+1 equal to 0.
y+1=0
Subtract 1 from both sides of the equation.
y=-1
Solve for y 5y^2+2y=4y^2-1

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