Solve for y 5y^2+4y+4=0

Math
5y2+4y+4=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=5, b=4, and c=4 into the quadratic formula and solve for y.
-4±42-4⋅(5⋅4)2⋅5
Simplify.
Tap for more steps…
Simplify the numerator.
Tap for more steps…
Raise 4 to the power of 2.
y=-4±16-4⋅(5⋅4)2⋅5
Multiply 5 by 4.
y=-4±16-4⋅202⋅5
Multiply -4 by 20.
y=-4±16-802⋅5
Subtract 80 from 16.
y=-4±-642⋅5
Rewrite -64 as -1(64).
y=-4±-1⋅642⋅5
Rewrite -1(64) as -1⋅64.
y=-4±-1⋅642⋅5
Rewrite -1 as i.
y=-4±i⋅642⋅5
Rewrite 64 as 82.
y=-4±i⋅822⋅5
Pull terms out from under the radical, assuming positive real numbers.
y=-4±i⋅82⋅5
Move 8 to the left of i.
y=-4±8i2⋅5
y=-4±8i2⋅5
Multiply 2 by 5.
y=-4±8i10
Simplify -4±8i10.
y=-2±4i5
y=-2±4i5
The final answer is the combination of both solutions.
y=-25+4i5,-25-4i5
Solve for y 5y^2+4y+4=0

Solving MATH problems

We can solve all math problems. Get help on the web or with our math app

Scroll to top