Solve for y 6(3/2)+3y=18

$6 (\frac{3}{2}) + 3 y = 18$

Simplify each term.

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Cancel the common factor of $2$ .

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Factor $2$ out of $6$ .

$2 (3) \frac{3}{2} + 3 y = 18$

Cancel the common factor.

$2 \cdot 3 \frac{3}{2} + 3 y = 18$

Rewrite the expression.

$3 \cdot 3 + 3 y = 18$

Multiply $3$ by $3$ .

$9 + 3 y = 18$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $9$ from both sides of the equation.

$3 y = 18 - 9$

Subtract $9$ from $18$ .

$3 y = 9$

Divide each term by $3$ and simplify.

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Divide each term in $3 y = 9$ by $3$ .

$\frac{3 y}{3} = \frac{9}{3}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 y}{3} = \frac{9}{3}$

Divide $y$ by $1$ .

$y = \frac{9}{3}$

Divide $9$ by $3$ .

$y = 3$

Solve for y 6(3/2)+3y=18