Solve for y y^2+4y-4=0

Math
y2+4y-4=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=4, and c=-4 into the quadratic formula and solve for y.
-4±42-4⋅(1⋅-4)2⋅1
Simplify.
Tap for more steps…
Simplify the numerator.
Tap for more steps…
Raise 4 to the power of 2.
y=-4±16-4⋅(1⋅-4)2⋅1
Multiply -4 by 1.
y=-4±16-4⋅-42⋅1
Multiply -4 by -4.
y=-4±16+162⋅1
Add 16 and 16.
y=-4±322⋅1
Rewrite 32 as 42⋅2.
Tap for more steps…
Factor 16 out of 32.
y=-4±16(2)2⋅1
Rewrite 16 as 42.
y=-4±42⋅22⋅1
y=-4±42⋅22⋅1
Pull terms out from under the radical.
y=-4±422⋅1
y=-4±422⋅1
Multiply 2 by 1.
y=-4±422
Simplify -4±422.
y=-2±22
y=-2±22
The final answer is the combination of both solutions.
y=-2+22,-2-22
The result can be shown in multiple forms.
Exact Form:
y=-2+22,-2-22
Decimal Form:
y=0.82842712…,-4.82842712…
Solve for y y^2+4y-4=0

Solving MATH problems

We can solve all math problems. Get help on the web or with our math app

Scroll to top