72+(40-4)=y65+z32

Rewrite the equation as y65+z32=72+40-4.

y65+z32=72+40-4

Add 72 and 40.

y65+z32=112-4

Subtract 4 from 112.

y65+z32=108

y65+z32=108

Subtract y65 from both sides of the equation.

z32=108-y65

Take the 32th root of both sides of the equation to eliminate the exponent on the left side.

z=±108-y6532

First, use the positive value of the ± to find the first solution.

z=108-y6532

Next, use the negative value of the ± to find the second solution.

z=-108-y6532

The complete solution is the result of both the positive and negative portions of the solution.

z=108-y6532

z=-108-y6532

z=108-y6532

z=-108-y6532

Solve for z 72+(40-4)=y^65+z^32