Solve for z 72+(40-4)=y^65+z^32

Math
72+(40-4)=y65+z32
Rewrite the equation as y65+z32=72+40-4.
y65+z32=72+40-4
Simplify 72+40-4.
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Add 72 and 40.
y65+z32=112-4
Subtract 4 from 112.
y65+z32=108
y65+z32=108
Subtract y65 from both sides of the equation.
z32=108-y65
Take the 32th root of both sides of the equation to eliminate the exponent on the left side.
z=±108-y6532
The complete solution is the result of both the positive and negative portions of the solution.
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First, use the positive value of the ± to find the first solution.
z=108-y6532
Next, use the negative value of the ± to find the second solution.
z=-108-y6532
The complete solution is the result of both the positive and negative portions of the solution.
z=108-y6532
z=-108-y6532
z=108-y6532
z=-108-y6532
Solve for z 72+(40-4)=y^65+z^32

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