Solve for z z^2+10z+24=0

Math
z2+10z+24=0
Factor z2+10z+24 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 24 and whose sum is 10.
4,6
Write the factored form using these integers.
(z+4)(z+6)=0
(z+4)(z+6)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
z+4=0
z+6=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
z+4=0
Subtract 4 from both sides of the equation.
z=-4
z=-4
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
z+6=0
Subtract 6 from both sides of the equation.
z=-6
z=-6
The final solution is all the values that make (z+4)(z+6)=0 true.
z=-4,-6
Solve for z z^2+10z+24=0

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