Solve for z z^2+14z+45=0

Math
z2+14z+45=0
Factor z2+14z+45 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 45 and whose sum is 14.
5,9
Write the factored form using these integers.
(z+5)(z+9)=0
(z+5)(z+9)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
z+5=0
z+9=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
z+5=0
Subtract 5 from both sides of the equation.
z=-5
z=-5
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
z+9=0
Subtract 9 from both sides of the equation.
z=-9
z=-9
The final solution is all the values that make (z+5)(z+9)=0 true.
z=-5,-9
Solve for z z^2+14z+45=0

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