# Solve using the Square Root Property n^2+6n=40 n2+6n=40
Move 40 to the left side of the equation by subtracting it from both sides.
n2+6n-40=0
Factor n2+6n-40 using the AC method.
Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -40 and whose sum is 6.
-4,10
Write the factored form using these integers.
(n-4)(n+10)=0
(n-4)(n+10)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
n-4=0
n+10=0
Set the first factor equal to 0 and solve.
Set the first factor equal to 0.
n-4=0
Add 4 to both sides of the equation.
n=4
n=4
Set the next factor equal to 0 and solve.
Set the next factor equal to 0.
n+10=0
Subtract 10 from both sides of the equation.
n=-10
n=-10
The final solution is all the values that make (n-4)(n+10)=0 true.
n=4,-10
Solve using the Square Root Property n^2+6n=40

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